What are the solutions to the equation x^3+4x^2+3x-2=0 ?

The solutions to the equation x^3+4x^2+3x-2=0 are x=-2,x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of x^3+4x^2+3x-2=0

The zeros of x^3+4x^2+3x-2=0 are x=-2,x=-1+sqrt(2),x=-1-sqrt(2)

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x^{3} + 4 x^{2} + 3 x - 2 = 0

x = - 2, x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = - 2, x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

x^{3} + 4 x^{2} + 3 x - 2 = 0

Factor

x^{3} + 4 x^{2} + 3 x - 2 : (x + 2) (x^{2} + 2 x - 1)

(x + 2) (x^{2} + 2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 2 x - 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 2 x - 1 = 0 : x = - 1 + 2, x = - 1 - 2

The solutions are

x = - 2, x = - 1 + 2, x = - 1 - 2

36 x^{3} - 100 x = 0

x^{4} + 2 x^{3} - 2 x - 1 = 0

x^{7} + 5 x^{3} + 6 = 0

2 x^{3} + 3 x^{2} - 8 x - 12 = 0

x^{3} = 125 x^{6}

What are the solutions to the equation x^3+4x^2+3x-2=0 ?
The solutions to the equation x^3+4x^2+3x-2=0 are x=-2,x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of x^3+4x^2+3x-2=0
The zeros of x^3+4x^2+3x-2=0 are x=-2,x=-1+sqrt(2),x=-1-sqrt(2)