What are the solutions to the equation (8x-7)(x^2-5)=0 ?

The solutions to the equation (8x-7)(x^2-5)=0 are x= 7/8 ,x=-sqrt(5),x=sqrt(5)

Find the zeros of (8x-7)(x^2-5)=0

The zeros of (8x-7)(x^2-5)=0 are x= 7/8 ,x=-sqrt(5),x=sqrt(5)

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(8 x - 7) (x^{2} - 5) = 0

x = \frac{7}{8}, x = - 5, x = 5

Decimal Notation

x = 0.875, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

(8 x - 7) (x^{2} - 5) = 0

Factor

(8 x - 7) (x^{2} - 5) : (8 x - 7) (x + 5) (x - 5)

(8 x - 7) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

8 x - 7 = 0 or x + 5 = 0 or x - 5 = 0

Solve

8 x - 7 = 0 : x = \frac{7}{8}

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = \frac{7}{8}, x = - 5, x = 5

2 x^{3} + 9 x^{2} + 13 x + 6 = 0

x^{4} + 6 x^{2} + 8 = 0

4 x^{3} + 16 x^{2} + 12 x = 0

(x^{2} - 1)^{2} + (x^{2} - 1) - 12 = 0

- x^{3} - 3 x^{2} + 25 x - 21 = 0

What are the solutions to the equation (8x-7)(x^2-5)=0 ?
The solutions to the equation (8x-7)(x^2-5)=0 are x= 7/8 ,x=-sqrt(5),x=sqrt(5)
Find the zeros of (8x-7)(x^2-5)=0
The zeros of (8x-7)(x^2-5)=0 are x= 7/8 ,x=-sqrt(5),x=sqrt(5)