What are the solutions to the equation 4x^3+x^2+100x+25=0 ?

The solutions to the equation 4x^3+x^2+100x+25=0 are x=-1/4 ,x=5i,x=-5i

Find the zeros of 4x^3+x^2+100x+25=0

The zeros of 4x^3+x^2+100x+25=0 are x=-1/4 ,x=5i,x=-5i

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4 x^{3} + x^{2} + 100 x + 25 = 0

x = - \frac{1}{4}, x = 5 i, x = - 5 i

Solution steps

4 x^{3} + x^{2} + 100 x + 25 = 0

Factor

4 x^{3} + x^{2} + 100 x + 25 : (4 x + 1) (x^{2} + 25)

(4 x + 1) (x^{2} + 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or x^{2} + 25 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x^{2} + 25 = 0 : x = 5 i, x = - 5 i

The solutions are

x = - \frac{1}{4}, x = 5 i, x = - 5 i

x^{3} + 3 x^{2} - x + 12 = 0

x^{4} - 2 x^{3} + 2 = - x + \frac{7}{4}

x^{3} + 1000 = 0

x^{3} - 3 x - 4 = 0

1 - 6 x^{2} x = 1 x - 8 x^{2}

What are the solutions to the equation 4x^3+x^2+100x+25=0 ?
The solutions to the equation 4x^3+x^2+100x+25=0 are x=-1/4 ,x=5i,x=-5i
Find the zeros of 4x^3+x^2+100x+25=0
The zeros of 4x^3+x^2+100x+25=0 are x=-1/4 ,x=5i,x=-5i