What are the solutions to the equation -3w^5-4w^3+w^2=0 ?

The solutions to the equation -3w^5-4w^3+w^2=0 are w=0,w\approx 0.23967…

Find the zeros of -3w^5-4w^3+w^2=0

The zeros of -3w^5-4w^3+w^2=0 are w=0,w\approx 0.23967…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 w^{5} - 4 w^{3} + w^{2} = 0

w = 0, w \approx 0.23967 \dots

Solution steps

- 3 w^{5} - 4 w^{3} + w^{2} = 0

Factor

- 3 w^{5} - 4 w^{3} + w^{2} : - w^{2} (3 w^{3} + 4 w - 1)

- w^{2} (3 w^{3} + 4 w - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

w = 0 or 3 w^{3} + 4 w - 1 = 0

Solve

3 w^{3} + 4 w - 1 = 0 : w \approx 0.23967 \dots

The solutions are

w = 0, w \approx 0.23967 \dots

x^{3} + 5 x = 0

3 x = x^{3}

3 x^{3} - x^{2} + 3 x - 1 = 0

50 x - 25 = 2 x^{3} - x^{2}

x^{3} + 729 = 0

What are the solutions to the equation -3w^5-4w^3+w^2=0 ?
The solutions to the equation -3w^5-4w^3+w^2=0 are w=0,w\approx 0.23967…
Find the zeros of -3w^5-4w^3+w^2=0
The zeros of -3w^5-4w^3+w^2=0 are w=0,w\approx 0.23967…