What are the solutions to the equation z^2+9=10z ?

The solutions to the equation z^2+9=10z are z=9,z=1

Find the zeros of z^2+9=10z

The zeros of z^2+9=10z are z=9,z=1

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z^{2} + 9 = 10 z

z = 9, z = 1

Solution steps

z^{2} + 9 = 10 z

Move

10 z

to the left side

z^{2} + 9 - 10 z = 0

Write in the standard form

a x^{2} + b x + c = 0

z^{2} - 10 z + 9 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 9 = 8

z_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 1}, z_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 1}

z = \frac{- ( - 10 ) + 8}{2 \cdot 1} : 9

z = \frac{- ( - 10 ) - 8}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

z = 9, z = 1

(\frac{6}{11})^{2}

\frac{4 x ^{4} y ^{2} z}{x ^{2} yz}

- 10 - 5 n^{2} = - 330

\frac{x}{- 4} \geq 8

2 d^{3} + 4 d

What are the solutions to the equation z^2+9=10z ?
The solutions to the equation z^2+9=10z are z=9,z=1
Find the zeros of z^2+9=10z
The zeros of z^2+9=10z are z=9,z=1