What are the solutions to the equation 3q^3=-8+D/A ?

The solutions to the equation 3q^3=-8+D/A are

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3q^3=-8+D/A

3 q^{3} = - 8 + \frac{D}{A}

Solution steps

3 q^{3} = - 8 + \frac{D}{A}

Divide both sides by

3

q^{3} = \frac{- 8 A + D}{3 A}

For

x^{3} = f (a)

the solutions are

Simplify

x^{3} - 15 x^{2} + 56 x = 0

y^{4} + 7 y^{2} - 144 = 0

2 (x^{2} - 5) (x^{2} + 100) = 0

7 x + x^{2} (x - 13) = 6

- 2 x^{4} + 9 = 3 x - 2

What are the solutions to the equation 3q^3=-8+D/A ?
The solutions to the equation 3q^3=-8+D/A are
Find the zeros of 3q^3=-8+D/A
The zeros of 3q^3=-8+D/A are