What are the solutions to the equation 4x^3-x^2+36x-9=0 ?

The solutions to the equation 4x^3-x^2+36x-9=0 are x= 1/4 ,x=3i,x=-3i

Find the zeros of 4x^3-x^2+36x-9=0

The zeros of 4x^3-x^2+36x-9=0 are x= 1/4 ,x=3i,x=-3i

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4 x^{3} - x^{2} + 36 x - 9 = 0

x = \frac{1}{4}, x = 3 i, x = - 3 i

Solution steps

4 x^{3} - x^{2} + 36 x - 9 = 0

Factor

4 x^{3} - x^{2} + 36 x - 9 : (4 x - 1) (x^{2} + 9)

(4 x - 1) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 1 = 0 or x^{2} + 9 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = \frac{1}{4}, x = 3 i, x = - 3 i

2 x^{3} + x - 2 = 0

x^{4} = 3

x^{4} = 8

8 x^{4} - 2 x^{2} - 1 = 0

x^{6} = 9 x^{4}

What are the solutions to the equation 4x^3-x^2+36x-9=0 ?
The solutions to the equation 4x^3-x^2+36x-9=0 are x= 1/4 ,x=3i,x=-3i
Find the zeros of 4x^3-x^2+36x-9=0
The zeros of 4x^3-x^2+36x-9=0 are x= 1/4 ,x=3i,x=-3i