What are the solutions to the equation d^3=27 ?

The solutions to the equation d^3=27 are d=3,d=-3/2+(3sqrt(3))/2 i,d=-3/2-(3sqrt(3))/2 i

Find the zeros of d^3=27

The zeros of d^3=27 are d=3,d=-3/2+(3sqrt(3))/2 i,d=-3/2-(3sqrt(3))/2 i

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d^{3} = 27

d = 3, d = - \frac{3}{2} + \frac{3 3}{2} i, d = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

d^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

d = 3, d = - \frac{3}{2} + \frac{3 3}{2} i, d = - \frac{3}{2} - \frac{3 3}{2} i

9 x^{4} - 46 x^{2} + 5 = 0

x^{5} - x + 1 = 0

32 x^{3} - 8 x^{7} = 0

x^{5} = 81 x^{3}

z^{6} = 64

What are the solutions to the equation d^3=27 ?
The solutions to the equation d^3=27 are d=3,d=-3/2+(3sqrt(3))/2 i,d=-3/2-(3sqrt(3))/2 i
Find the zeros of d^3=27
The zeros of d^3=27 are d=3,d=-3/2+(3sqrt(3))/2 i,d=-3/2-(3sqrt(3))/2 i