What are the solutions to the equation -x(x+6)(x^2-49)=0 ?

The solutions to the equation -x(x+6)(x^2-49)=0 are x=0,x=-6,x=-7,x=7

Find the zeros of -x(x+6)(x^2-49)=0

The zeros of -x(x+6)(x^2-49)=0 are x=0,x=-6,x=-7,x=7

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- x (x + 6) (x^{2} - 49) = 0

x = 0, x = - 6, x = - 7, x = 7

Solution steps

- x (x + 6) (x^{2} - 49) = 0

Factor

- x (x + 6) (x^{2} - 49) : - x (x + 6) (x + 7) (x - 7)

- x (x + 6) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 6 = 0 or x + 7 = 0 or x - 7 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = - 6, x = - 7, x = 7

p^{3} = - 0.027

lo g_{2} (16) = \frac{x ^{3}}{2}

9 x^{4} - 13 x^{2} + 4 = 0

- 10 n^{3} - 15 n^{4} = - 5 n^{3}

x^{3} - 4 x^{2} + 3 x - 2 = 0

What are the solutions to the equation -x(x+6)(x^2-49)=0 ?
The solutions to the equation -x(x+6)(x^2-49)=0 are x=0,x=-6,x=-7,x=7
Find the zeros of -x(x+6)(x^2-49)=0
The zeros of -x(x+6)(x^2-49)=0 are x=0,x=-6,x=-7,x=7