What are the solutions to the equation 3x^4=648x ?

The solutions to the equation 3x^4=648x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

Find the zeros of 3x^4=648x

The zeros of 3x^4=648x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

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3 x^{4} = 648 x

x = 0, x = 6, x = - 3 + 33 i, x = - 3 - 33 i

Solution steps

3 x^{4} = 648 x

Move

648 x

to the left side

3 x^{4} - 648 x = 0

Factor

3 x^{4} - 648 x : 3 x (x - 6) (x^{2} + 6 x + 36)

3 x (x - 6) (x^{2} + 6 x + 36) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 6 = 0 or x^{2} + 6 x + 36 = 0

Solve

x - 6 = 0 : x = 6

Solve

x^{2} + 6 x + 36 = 0 : x = - 3 + 33 i, x = - 3 - 33 i

The solutions are

x = 0, x = 6, x = - 3 + 33 i, x = - 3 - 33 i

- 2 x^{4} + 7 = 3 x - 2

3 x^{3} + 4 x^{2} = 27 x + 36

a^{10} = - 3 \cdot (- 2^{(10 - 1)})

x^{5} + 2 x - 3 = 0

X = X (X - 2)^{2}

What are the solutions to the equation 3x^4=648x ?
The solutions to the equation 3x^4=648x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i
Find the zeros of 3x^4=648x
The zeros of 3x^4=648x are x=0,x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i