What are the solutions to the equation e=(m^8)3m^{21} ?

The solutions to the equation e=(m^8)3m^{21} are m=\sqrt[29]{e/3}

Find the zeros of e=(m^8)3m^{21}

The zeros of e=(m^8)3m^{21} are m=\sqrt[29]{e/3}

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e = (m^{8}) 3 m^{21}

Decimal Notation

m = 0.99660 \dots

Solution steps

e = (m^{8}) \cdot 3 m^{21}

Switch sides

(m^{8}) \cdot 3 m^{21} = e

Simplify

3 m^{29} = e

Divide both sides by

3

\frac{3 m ^{29}}{3} = \frac{e}{3}

m^{29} = \frac{e}{3}

For

x^{n} = f (a)

, n is odd, the solution is

3 x^{3} + 4 x^{2} - 7 x + 2 = 0

2 x^{2} + 15 x = x^{3}

x^{8} + 3 x^{4} = 4

x^{3} - 4 x^{2} - 45 x = 0

x^{4} - 3 x^{2} - 12 = 0

What are the solutions to the equation e=(m^8)3m^{21} ?
The solutions to the equation e=(m^8)3m^{21} are m=\sqrt[29]{e/3}
Find the zeros of e=(m^8)3m^{21}
The zeros of e=(m^8)3m^{21} are m=\sqrt[29]{e/3}