What are the solutions to the equation 5x(x^2-2)=10x(x-1) ?

The solutions to the equation 5x(x^2-2)=10x(x-1) are x=0,x=2

Find the zeros of 5x(x^2-2)=10x(x-1)

The zeros of 5x(x^2-2)=10x(x-1) are x=0,x=2

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5 x (x^{2} - 2) = 10 x (x - 1)

x = 0, x = 2

Solution steps

5 x (x^{2} - 2) = 10 x (x - 1)

Move

10 x (x - 1)

to the left side

5 x (x^{2} - 2) - 10 x (x - 1) = 0

Factor

5 x (x^{2} - 2) - 10 x (x - 1) : 5 x^{2} (x - 2)

5 x^{2} (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 2

- x^{3} + x + 2 = 0

n^{4} + 15 = 38

x^{3} + 6 x^{2} + 13 x = 0

x^{3} - 10 x^{2} + 16 x = 0

4 x^{3} - 1 = 0

What are the solutions to the equation 5x(x^2-2)=10x(x-1) ?
The solutions to the equation 5x(x^2-2)=10x(x-1) are x=0,x=2
Find the zeros of 5x(x^2-2)=10x(x-1)
The zeros of 5x(x^2-2)=10x(x-1) are x=0,x=2