What are the solutions to the equation -3(36x^2-25)(x^2+1)=0 ?

The solutions to the equation -3(36x^2-25)(x^2+1)=0 are x=-5/6 ,x= 5/6 ,x=i,x=-i

Find the zeros of -3(36x^2-25)(x^2+1)=0

The zeros of -3(36x^2-25)(x^2+1)=0 are x=-5/6 ,x= 5/6 ,x=i,x=-i

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- 3 (36 x^{2} - 25) (x^{2} + 1) = 0

x = - \frac{5}{6}, x = \frac{5}{6}, x = i, x = - i

Solution steps

- 3 (36 x^{2} - 25) (x^{2} + 1) = 0

Factor

- 3 (36 x^{2} - 25) (x^{2} + 1) : - 3 (6 x + 5) (6 x - 5) (x^{2} + 1)

- 3 (6 x + 5) (6 x - 5) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x + 5 = 0 or 6 x - 5 = 0 or x^{2} + 1 = 0

Solve

6 x + 5 = 0 : x = - \frac{5}{6}

Solve

6 x - 5 = 0 : x = \frac{5}{6}

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = - \frac{5}{6}, x = \frac{5}{6}, x = i, x = - i

- 2 (x + 8) (25 x^{2} - 49) = 0

k^{3} + 30 k = - 13 k^{2}

- x^{3} + 3 x^{2} - 4 = 0

x (x^{2} - 3) - x (x + 3) = 0

x^{4} - 13 x^{2} + 42 = 0

What are the solutions to the equation -3(36x^2-25)(x^2+1)=0 ?
The solutions to the equation -3(36x^2-25)(x^2+1)=0 are x=-5/6 ,x= 5/6 ,x=i,x=-i
Find the zeros of -3(36x^2-25)(x^2+1)=0
The zeros of -3(36x^2-25)(x^2+1)=0 are x=-5/6 ,x= 5/6 ,x=i,x=-i