What are the solutions to the equation x^3-x^2+9x-9=0 ?

The solutions to the equation x^3-x^2+9x-9=0 are x=1,x=3i,x=-3i

Find the zeros of x^3-x^2+9x-9=0

The zeros of x^3-x^2+9x-9=0 are x=1,x=3i,x=-3i

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x^{3} - x^{2} + 9 x - 9 = 0

x = 1, x = 3 i, x = - 3 i

Solution steps

x^{3} - x^{2} + 9 x - 9 = 0

Factor

x^{3} - x^{2} + 9 x - 9 : (x - 1) (x^{2} + 9)

(x - 1) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} + 9 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = 1, x = 3 i, x = - 3 i

x^{3} - 18 x^{2} + 80 x = 0

b, a = 4 b^{5} h

x^{3} - 7 x^{2} - 4 x + 28 = 0

- x^{3} + 3 x^{2} - 2 x = 0

32 = x^{5}

What are the solutions to the equation x^3-x^2+9x-9=0 ?
The solutions to the equation x^3-x^2+9x-9=0 are x=1,x=3i,x=-3i
Find the zeros of x^3-x^2+9x-9=0
The zeros of x^3-x^2+9x-9=0 are x=1,x=3i,x=-3i