What are the solutions to the equation t^3-12t^2+41t-30=0 ?

The solutions to the equation t^3-12t^2+41t-30=0 are t=1,t=5,t=6

Find the zeros of t^3-12t^2+41t-30=0

The zeros of t^3-12t^2+41t-30=0 are t=1,t=5,t=6

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t^{3} - 12 t^{2} + 41 t - 30 = 0

t = 1, t = 5, t = 6

Solution steps

t^{3} - 12 t^{2} + 41 t - 30 = 0

Factor

t^{3} - 12 t^{2} + 41 t - 30 : (t - 1) (t - 5) (t - 6)

(t - 1) (t - 5) (t - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t - 1 = 0 or t - 5 = 0 or t - 6 = 0

Solve

t - 1 = 0 : t = 1

Solve

t - 5 = 0 : t = 5

Solve

t - 6 = 0 : t = 6

The solutions are

t = 1, t = 5, t = 6

4 x^{4} = 864 x

7 x^{4} = 448 x

- 5 x^{4} - 20 x^{3} = 0

2 x^{3} - x^{2} + 6 x - 3 = 0

x^{4} - 3 x^{3} - 11 x^{2} + 3 x + 10 = 0

What are the solutions to the equation t^3-12t^2+41t-30=0 ?
The solutions to the equation t^3-12t^2+41t-30=0 are t=1,t=5,t=6
Find the zeros of t^3-12t^2+41t-30=0
The zeros of t^3-12t^2+41t-30=0 are t=1,t=5,t=6