What are the solutions to the equation x^3+5nx^2-4x-20n=0 ?

The solutions to the equation x^3+5nx^2-4x-20n=0 are x=-5n,x=-2,x=2

Find the zeros of x^3+5nx^2-4x-20n=0

The zeros of x^3+5nx^2-4x-20n=0 are x=-5n,x=-2,x=2

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x^{3} + 5 n x^{2} - 4 x - 20 n = 0

x = - 5 n, x = - 2, x = 2

Solution steps

x^{3} + 5 n x^{2} - 4 x - 20 n = 0

Factor

x^{3} + 5 n x^{2} - 4 x - 20 n : (x + 5 n) (x + 2) (x - 2)

(x + 5 n) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 n = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 5 n = 0 : x = - 5 n

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 5 n, x = - 2, x = 2

(x^{2} + 5)^{4} = 16

- 2 x^{4} + 5 = 3 x - 2

x^{4} - 2 x^{3} + 2 x^{2} - 2 x = 0

0 = 4 x^{3} - 4 x

x^{3} - 6 x^{2} - 5 x + 30 = 0

What are the solutions to the equation x^3+5nx^2-4x-20n=0 ?
The solutions to the equation x^3+5nx^2-4x-20n=0 are x=-5n,x=-2,x=2
Find the zeros of x^3+5nx^2-4x-20n=0
The zeros of x^3+5nx^2-4x-20n=0 are x=-5n,x=-2,x=2