What are the solutions to the equation 2r^4+5r^3+r^2-2r=0 ?

The solutions to the equation 2r^4+5r^3+r^2-2r=0 are r=0,r=-1,r= 1/2 ,r=-2

Find the zeros of 2r^4+5r^3+r^2-2r=0

The zeros of 2r^4+5r^3+r^2-2r=0 are r=0,r=-1,r= 1/2 ,r=-2

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2 r^{4} + 5 r^{3} + r^{2} - 2 r = 0

r = 0, r = - 1, r = \frac{1}{2}, r = - 2

Decimal Notation

r = 0, r = - 1, r = 0.5, r = - 2

Solution steps

2 r^{4} + 5 r^{3} + r^{2} - 2 r = 0

Factor

2 r^{4} + 5 r^{3} + r^{2} - 2 r : r (r + 1) (2 r - 1) (r + 2)

r (r + 1) (2 r - 1) (r + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r = 0 or r + 1 = 0 or 2 r - 1 = 0 or r + 2 = 0

Solve

r + 1 = 0 : r = - 1

Solve

2 r - 1 = 0 : r = \frac{1}{2}

Solve

r + 2 = 0 : r = - 2

The solutions are

r = 0, r = - 1, r = \frac{1}{2}, r = - 2

y^{3} = 0

- x^{3} + 11 x^{2} - 36 x + 36 = 0

x^{3} + 4 x^{2} + 5 x = 0

6 (x + 2)^{5} = 64

7 x^{4} - 28 x^{2} = 0

What are the solutions to the equation 2r^4+5r^3+r^2-2r=0 ?
The solutions to the equation 2r^4+5r^3+r^2-2r=0 are r=0,r=-1,r= 1/2 ,r=-2
Find the zeros of 2r^4+5r^3+r^2-2r=0
The zeros of 2r^4+5r^3+r^2-2r=0 are r=0,r=-1,r= 1/2 ,r=-2