What are the solutions to the equation x^3-5x^2+4x=0 ?

The solutions to the equation x^3-5x^2+4x=0 are x=0,x=1,x=4

Find the zeros of x^3-5x^2+4x=0

The zeros of x^3-5x^2+4x=0 are x=0,x=1,x=4

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x^{3} - 5 x^{2} + 4 x = 0

x = 0, x = 1, x = 4

Solution steps

x^{3} - 5 x^{2} + 4 x = 0

Factor

x^{3} - 5 x^{2} + 4 x : x (x - 1) (x - 4)

x (x - 1) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = 1, x = 4

(x^{2} + x - 2) (x - 1) = 0

4 x^{4} - 10 x^{2} + 9 = 0

x^{5} = \frac{1}{32}

(x^{2} - 7)^{2} = 25

x, x^{3} = y^{2}

What are the solutions to the equation x^3-5x^2+4x=0 ?
The solutions to the equation x^3-5x^2+4x=0 are x=0,x=1,x=4
Find the zeros of x^3-5x^2+4x=0
The zeros of x^3-5x^2+4x=0 are x=0,x=1,x=4