What are the solutions to the equation 3x^3+4x^2-21x-28=0 ?

The solutions to the equation 3x^3+4x^2-21x-28=0 are x=-4/3 ,x=-sqrt(7),x=sqrt(7)

Find the zeros of 3x^3+4x^2-21x-28=0

The zeros of 3x^3+4x^2-21x-28=0 are x=-4/3 ,x=-sqrt(7),x=sqrt(7)

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3 x^{3} + 4 x^{2} - 21 x - 28 = 0

x = - \frac{4}{3}, x = - 7, x = 7

Decimal Notation

x = - 1.33333 \dots, x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

3 x^{3} + 4 x^{2} - 21 x - 28 = 0

Factor

3 x^{3} + 4 x^{2} - 21 x - 28 : (3 x + 4) (x + 7) (x - 7)

(3 x + 4) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 4 = 0 or x + 7 = 0 or x - 7 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = - \frac{4}{3}, x = - 7, x = 7

0 = 4 x^{3} - 16 x

(x + 1) (x + 2) (x + 3) = 0

6 x (x^{2} - 1)^{2} = 0

x^{3} + 2 x - 400 = 0

x^{3} + 2 x^{2} - 13 x + 10 = 0

What are the solutions to the equation 3x^3+4x^2-21x-28=0 ?
The solutions to the equation 3x^3+4x^2-21x-28=0 are x=-4/3 ,x=-sqrt(7),x=sqrt(7)
Find the zeros of 3x^3+4x^2-21x-28=0
The zeros of 3x^3+4x^2-21x-28=0 are x=-4/3 ,x=-sqrt(7),x=sqrt(7)