What are the solutions to the equation ((4x-7)/3)^3=27 ?

The solutions to the equation ((4x-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8

Find the zeros of ((4x-7)/3)^3=27

The zeros of ((4x-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8

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(\frac{4 x - 7}{3})^{3} = 27

x = 4, x = \frac{5}{8} + i \frac{9 3}{8}, x = \frac{5}{8} - i \frac{9 3}{8}

Solution steps

(\frac{4 x - 7}{3})^{3} = 27

For

g^{3} (x) = f (a)

the solutions are

g (x) = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

Solve

\frac{4 x - 7}{3} = 327 : x = 4

Solve

\frac{4 x - 7}{3} = 327 \frac{- 1 + 3 i}{2} : x = \frac{5}{8} + i \frac{9 3}{8}

Solve

\frac{4 x - 7}{3} = 327 \frac{- 1 - 3 i}{2} : x = \frac{5}{8} - i \frac{9 3}{8}

The solutions are

x = 4, x = \frac{5}{8} + i \frac{9 3}{8}, x = \frac{5}{8} - i \frac{9 3}{8}

x^{3} + 5 x^{2} = - 6 x

x, x^{3} - 2 x^{2} - 5 x + 6 = 0

2 x^{3} - 7 x^{2} + 32 x - 112 = 0

F, t = (F^{3} + G) a

y^{3} + 2 y^{2} = 9 y + 18

What are the solutions to the equation ((4x-7)/3)^3=27 ?
The solutions to the equation ((4x-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8
Find the zeros of ((4x-7)/3)^3=27
The zeros of ((4x-7)/3)^3=27 are x=4,x= 5/8+i(9sqrt(3))/8 ,x= 5/8-i(9sqrt(3))/8