What are the solutions to the equation x^4-6x^3-8x^2+96x-128=0 ?

The solutions to the equation x^4-6x^3-8x^2+96x-128=0 are x=2,x=4,x=-4

Find the zeros of x^4-6x^3-8x^2+96x-128=0

The zeros of x^4-6x^3-8x^2+96x-128=0 are x=2,x=4,x=-4

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x^{4} - 6 x^{3} - 8 x^{2} + 96 x - 128 = 0

x = 2, x = 4, x = - 4

Solution steps

x^{4} - 6 x^{3} - 8 x^{2} + 96 x - 128 = 0

Factor

x^{4} - 6 x^{3} - 8 x^{2} + 96 x - 128 : (x - 2) (x - 4)^{2} (x + 4)

(x - 2) (x - 4)^{2} (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 4 = 0 or x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 2, x = 4, x = - 4

10 = 500 (x)^{3}

x^{3} - 6 x^{2} - 15 x - 8 = 0

x^{3} + 2 x - 2 = 0

x^{3} - x^{2} - 6 = 0

x^{4} - 24 x^{2} - 25 = 0

What are the solutions to the equation x^4-6x^3-8x^2+96x-128=0 ?
The solutions to the equation x^4-6x^3-8x^2+96x-128=0 are x=2,x=4,x=-4
Find the zeros of x^4-6x^3-8x^2+96x-128=0
The zeros of x^4-6x^3-8x^2+96x-128=0 are x=2,x=4,x=-4