What are the solutions to the equation -x^3-x^2-x-1=0 ?

The solutions to the equation -x^3-x^2-x-1=0 are x=-1,x=i,x=-i

Find the zeros of -x^3-x^2-x-1=0

The zeros of -x^3-x^2-x-1=0 are x=-1,x=i,x=-i

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- x^{3} - x^{2} - x - 1 = 0

x = - 1, x = i, x = - i

Solution steps

- x^{3} - x^{2} - x - 1 = 0

Factor

- x^{3} - x^{2} - x - 1 : - (x + 1) (x^{2} + 1)

- (x + 1) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} + 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = - 1, x = i, x = - i

x^{4} - 6 x^{2} = - 8

x^{3} - 19 x + 30 = 0

8 x^{5} + 2 x^{4} - 3 x^{3} = 0

25 x^{3} - 16 x = 0

25 x^{4} - 20 x^{2} + 3 = 0

What are the solutions to the equation -x^3-x^2-x-1=0 ?
The solutions to the equation -x^3-x^2-x-1=0 are x=-1,x=i,x=-i
Find the zeros of -x^3-x^2-x-1=0
The zeros of -x^3-x^2-x-1=0 are x=-1,x=i,x=-i