What are the solutions to the equation x^3-12x+10=0 ?

The solutions to the equation x^3-12x+10=0 are x\approx 0.89259…,x\approx 2.93045…,x\approx-3.82305…

Find the zeros of x^3-12x+10=0

The zeros of x^3-12x+10=0 are x\approx 0.89259…,x\approx 2.93045…,x\approx-3.82305…

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x^{3} - 12 x + 10 = 0

x \approx 0.89259 \dots, x \approx 2.93045 \dots, x \approx - 3.82305 \dots

Solution steps

x^{3} - 12 x + 10 = 0

Find one solution for

x^{3} - 12 x + 10 = 0

using Newton-Raphson:

x \approx 0.89259 \dots

Apply long division:

\frac{x ^{3} - 12 x + 10}{x - 0.89259 \dots} = x^{2} + 0.89259 \dots x - 11.20327 \dots

x^{2} + 0.89259 \dots x - 11.20327 \dots \approx 0

Find one solution for

x^{2} + 0.89259 \dots x - 11.20327 \dots = 0

using Newton-Raphson:

x \approx 2.93045 \dots

Apply long division:

\frac{x ^{2} + 0.89259 \dots x - 11.20327 \dots}{x - 2.93045 \dots} = x + 3.82305 \dots

x + 3.82305 \dots \approx 0

x \approx - 3.82305 \dots

The solutions are

x \approx 0.89259 \dots, x \approx 2.93045 \dots, x \approx - 3.82305 \dots

x^{9} + 3 x^{6} + 3 x^{3} - 16 x + 9 = 0

x^{3} - 5 x^{2} + 4 x - 1 = 0

- x^{3} - 2 x^{2} + x + 2 = 0

(x - 2)^{3} = 3 x - 6

x^{4} - 8 x^{2} = 9

What are the solutions to the equation x^3-12x+10=0 ?
The solutions to the equation x^3-12x+10=0 are x\approx 0.89259…,x\approx 2.93045…,x\approx-3.82305…
Find the zeros of x^3-12x+10=0
The zeros of x^3-12x+10=0 are x\approx 0.89259…,x\approx 2.93045…,x\approx-3.82305…