What are the solutions to the equation x^4-17x+16=0 ?

The solutions to the equation x^4-17x+16=0 are x=1,x\approx 2.11236…

Find the zeros of x^4-17x+16=0

The zeros of x^4-17x+16=0 are x=1,x\approx 2.11236…

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x^{4} - 17 x + 16 = 0

x = 1, x \approx 2.11236 \dots

Solution steps

x^{4} - 17 x + 16 = 0

Factor

x^{4} - 17 x + 16 : (x - 1) (x^{3} + x^{2} + x - 16)

(x - 1) (x^{3} + x^{2} + x - 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{3} + x^{2} + x - 16 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{3} + x^{2} + x - 16 = 0 : x \approx 2.11236 \dots

The solutions are

x = 1, x \approx 2.11236 \dots

x^{4} + 2 x^{3} = 0

8 x^{3} - 64 = 0

2 x^{3} - 3 x - 2 = 0

2 x^{3} - 6 x^{2} + 8 x - 2508 = 0

2 x^{3} + x^{2} + 2 x + 1 = 0

What are the solutions to the equation x^4-17x+16=0 ?
The solutions to the equation x^4-17x+16=0 are x=1,x\approx 2.11236…
Find the zeros of x^4-17x+16=0
The zeros of x^4-17x+16=0 are x=1,x\approx 2.11236…