What are the solutions to the equation 2x^5+5x^4-3x^2=0 ?

The solutions to the equation 2x^5+5x^4-3x^2=0 are x=0,x=-1,x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4

Find the zeros of 2x^5+5x^4-3x^2=0

The zeros of 2x^5+5x^4-3x^2=0 are x=0,x=-1,x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4

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2 x^{5} + 5 x^{4} - 3 x^{2} = 0

x = 0, x = - 1, x = \frac{- 3 + 33}{4}, x = \frac{- 3 - 33}{4}

Decimal Notation

x = 0, x = - 1, x = 0.68614 \dots, x = - 2.18614 \dots

Solution steps

2 x^{5} + 5 x^{4} - 3 x^{2} = 0

Factor

2 x^{5} + 5 x^{4} - 3 x^{2} : x^{2} (x + 1) (2 x^{2} + 3 x - 3)

x^{2} (x + 1) (2 x^{2} + 3 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or 2 x^{2} + 3 x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x^{2} + 3 x - 3 = 0 : x = \frac{- 3 + 33}{4}, x = \frac{- 3 - 33}{4}

The solutions are

x = 0, x = - 1, x = \frac{- 3 + 33}{4}, x = \frac{- 3 - 33}{4}

x^{6} + 7 x^{3} = 8

16 = r^{4}

x^{4} - 11 x^{2} + 28 = 0

x^{4} - 4 x^{2} - 5 = 0

x^{3} - 12 x^{2} + 35 x = 0

What are the solutions to the equation 2x^5+5x^4-3x^2=0 ?
The solutions to the equation 2x^5+5x^4-3x^2=0 are x=0,x=-1,x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4
Find the zeros of 2x^5+5x^4-3x^2=0
The zeros of 2x^5+5x^4-3x^2=0 are x=0,x=-1,x=(-3+sqrt(33))/4 ,x=(-3-sqrt(33))/4