What are the solutions to the equation -x^3-3x^2-3x-1=0 ?

The solutions to the equation -x^3-3x^2-3x-1=0 are x=-1

Find the zeros of -x^3-3x^2-3x-1=0

The zeros of -x^3-3x^2-3x-1=0 are x=-1

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- x^{3} - 3 x^{2} - 3 x - 1 = 0

x = - 1

Solution steps

- x^{3} - 3 x^{2} - 3 x - 1 = 0

Factor

- x^{3} - 3 x^{2} - 3 x - 1 : - (x + 1)^{3}

- (x + 1)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0

Solve

x + 1 = 0 : x = - 1

The solution is

x = - 1

z^{4} + 16 z^{2} - 225 = 0

x^{6} - x^{2} = 0

x, x^{3} - 64 = 0

- r^{3} + 4 r^{2} - 6 r + 4 = 0

8 n^{3} - 4 n^{2} = 18 n - 9

What are the solutions to the equation -x^3-3x^2-3x-1=0 ?
The solutions to the equation -x^3-3x^2-3x-1=0 are x=-1
Find the zeros of -x^3-3x^2-3x-1=0
The zeros of -x^3-3x^2-3x-1=0 are x=-1