What are the solutions to the equation x^3-5x^2+4=0 ?

The solutions to the equation x^3-5x^2+4=0 are x=1,x=2(1+sqrt(2)),x=2(1-sqrt(2))

Find the zeros of x^3-5x^2+4=0

The zeros of x^3-5x^2+4=0 are x=1,x=2(1+sqrt(2)),x=2(1-sqrt(2))

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x^{3} - 5 x^{2} + 4 = 0

x = 1, x = 2 (1 + 2), x = 2 (1 - 2)

Decimal Notation

x = 1, x = 4.82842 \dots, x = - 0.82842 \dots

Solution steps

x^{3} - 5 x^{2} + 4 = 0

Factor

x^{3} - 5 x^{2} + 4 : (x - 1) (x^{2} - 4 x - 4)

(x - 1) (x^{2} - 4 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 4 x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 4 x - 4 = 0 : x = 2 (1 + 2), x = 2 (1 - 2)

The solutions are

x = 1, x = 2 (1 + 2), x = 2 (1 - 2)

2 x^{3} - 10 x^{2} = 72 x

p^{3} = 64

8 z^{3} - 125 = 0

x^{4} = 9 x^{2}

x^{3} - 3 x^{2} = - 2 x + 6

What are the solutions to the equation x^3-5x^2+4=0 ?
The solutions to the equation x^3-5x^2+4=0 are x=1,x=2(1+sqrt(2)),x=2(1-sqrt(2))
Find the zeros of x^3-5x^2+4=0
The zeros of x^3-5x^2+4=0 are x=1,x=2(1+sqrt(2)),x=2(1-sqrt(2))