What are the solutions to the equation 6^2+b^2=(6sqrt(2))^2 ?

The solutions to the equation 6^2+b^2=(6sqrt(2))^2 are b=6,b=-6

Find the zeros of 6^2+b^2=(6sqrt(2))^2

The zeros of 6^2+b^2=(6sqrt(2))^2 are b=6,b=-6

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6^{2} + b^{2} = (62)^{2}

b = 6, b = - 6

Solution steps

6^{2} + b^{2} = (62)^{2}

Expand

6^{2} + b^{2} : 36 + b^{2}

Expand

(62)^{2} : 72

36 + b^{2} = 72

Move

36

to the right side

b^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 36, b = - 36

36 = 6

- 36 = - 6

b = 6, b = - 6

\frac{4}{10} x - 3 x + \frac{8}{5} = \frac{4}{5}

x + \frac{1}{3} = \frac{x}{3}

27 - 8 y^{3}

3 x (x + 3) \geq 2 (x + 3)

\frac{8.4}{7.5} = \frac{x}{5}

What are the solutions to the equation 6^2+b^2=(6sqrt(2))^2 ?
The solutions to the equation 6^2+b^2=(6sqrt(2))^2 are b=6,b=-6
Find the zeros of 6^2+b^2=(6sqrt(2))^2
The zeros of 6^2+b^2=(6sqrt(2))^2 are b=6,b=-6