What are the solutions to the equation 4x^3+x^2-12x-3=0 ?

The solutions to the equation 4x^3+x^2-12x-3=0 are x=-1/4 ,x=-sqrt(3),x=sqrt(3)

Find the zeros of 4x^3+x^2-12x-3=0

The zeros of 4x^3+x^2-12x-3=0 are x=-1/4 ,x=-sqrt(3),x=sqrt(3)

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4 x^{3} + x^{2} - 12 x - 3 = 0

x = - \frac{1}{4}, x = - 3, x = 3

Decimal Notation

x = - 0.25, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

4 x^{3} + x^{2} - 12 x - 3 = 0

Factor

4 x^{3} + x^{2} - 12 x - 3 : (4 x + 1) (x + 3) (x - 3)

(4 x + 1) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - \frac{1}{4}, x = - 3, x = 3

x^{4} - x^{3} - 30 x^{2} = 0

x^{3} + 5 x^{2} - 3 x - 15 = 0

- 12 - 12 x + 18 x^{2} - 2.75 x^{3} = 0

- x^{3} + 2 x^{2} = 0

x^{3} + 3 b x^{2} - 16 x - 48 b = 0

What are the solutions to the equation 4x^3+x^2-12x-3=0 ?
The solutions to the equation 4x^3+x^2-12x-3=0 are x=-1/4 ,x=-sqrt(3),x=sqrt(3)
Find the zeros of 4x^3+x^2-12x-3=0
The zeros of 4x^3+x^2-12x-3=0 are x=-1/4 ,x=-sqrt(3),x=sqrt(3)