What are the solutions to the equation -a^3+2a^2+5a-6=0 ?

The solutions to the equation -a^3+2a^2+5a-6=0 are a=1,a=-2,a=3

Find the zeros of -a^3+2a^2+5a-6=0

The zeros of -a^3+2a^2+5a-6=0 are a=1,a=-2,a=3

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- a^{3} + 2 a^{2} + 5 a - 6 = 0

a = 1, a = - 2, a = 3

Solution steps

- a^{3} + 2 a^{2} + 5 a - 6 = 0

Factor

- a^{3} + 2 a^{2} + 5 a - 6 : - (a - 1) (a + 2) (a - 3)

- (a - 1) (a + 2) (a - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a - 1 = 0 or a + 2 = 0 or a - 3 = 0

Solve

a - 1 = 0 : a = 1

Solve

a + 2 = 0 : a = - 2

Solve

a - 3 = 0 : a = 3

The solutions are

a = 1, a = - 2, a = 3

x^{3} + 9 x = 26

x^{3} + 8 x^{2} - 64 x - 512 = 0

0 = x^{3}

x^{(3)} + 2 x^{(2)} - 11 x - 12 = 0

x^{3} - 14 x^{2} + 50 x = 0

What are the solutions to the equation -a^3+2a^2+5a-6=0 ?
The solutions to the equation -a^3+2a^2+5a-6=0 are a=1,a=-2,a=3
Find the zeros of -a^3+2a^2+5a-6=0
The zeros of -a^3+2a^2+5a-6=0 are a=1,a=-2,a=3