What are the solutions to the equation -2x(100x^2-9)(x^2+81)=0 ?

The solutions to the equation -2x(100x^2-9)(x^2+81)=0 are x=0,x=-3/10 ,x= 3/10 ,x=9i,x=-9i

Find the zeros of -2x(100x^2-9)(x^2+81)=0

The zeros of -2x(100x^2-9)(x^2+81)=0 are x=0,x=-3/10 ,x= 3/10 ,x=9i,x=-9i

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- 2 x (100 x^{2} - 9) (x^{2} + 81) = 0

x = 0, x = - \frac{3}{10}, x = \frac{3}{10}, x = 9 i, x = - 9 i

Solution steps

- 2 x (100 x^{2} - 9) (x^{2} + 81) = 0

Factor

- 2 x (100 x^{2} - 9) (x^{2} + 81) : - 2 x (10 x + 3) (10 x - 3) (x^{2} + 81)

- 2 x (10 x + 3) (10 x - 3) (x^{2} + 81) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 10 x + 3 = 0 or 10 x - 3 = 0 or x^{2} + 81 = 0

Solve

10 x + 3 = 0 : x = - \frac{3}{10}

Solve

10 x - 3 = 0 : x = \frac{3}{10}

Solve

x^{2} + 81 = 0 : x = 9 i, x = - 9 i

The solutions are

x = 0, x = - \frac{3}{10}, x = \frac{3}{10}, x = 9 i, x = - 9 i

7 x^{4} - 63 x^{2} = 0

5 x^{3} + 18 x^{2} = 8 x

- (- 10 x + 1) - 4 x = 7 x^{7} x

4 x^{3} + 4 x^{2} - 25 x - 25 = 0

- x^{3} + 8 x^{2} - 19 x + 12 = 0

What are the solutions to the equation -2x(100x^2-9)(x^2+81)=0 ?
The solutions to the equation -2x(100x^2-9)(x^2+81)=0 are x=0,x=-3/10 ,x= 3/10 ,x=9i,x=-9i
Find the zeros of -2x(100x^2-9)(x^2+81)=0
The zeros of -2x(100x^2-9)(x^2+81)=0 are x=0,x=-3/10 ,x= 3/10 ,x=9i,x=-9i