What are the solutions to the equation z^3+27=0 ?

The solutions to the equation z^3+27=0 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i

Find the zeros of z^3+27=0

The zeros of z^3+27=0 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i

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z^{3} + 27 = 0

z = - 3, z = \frac{3}{2} - \frac{3 3}{2} i, z = \frac{3}{2} + \frac{3 3}{2} i

Solution steps

z^{3} + 27 = 0

Move

27

to the right side

z^{3} = - 27

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

z = 3 - 27, z = 3 - 27 \frac{- 1 + 3 i}{2}, z = 3 - 27 \frac{- 1 - 3 i}{2}

3 - 27 = - 3

Simplify

3 - 27 \frac{- 1 + 3 i}{2} : \frac{3}{2} - \frac{3 3}{2} i

Simplify

3 - 27 \frac{- 1 - 3 i}{2} : \frac{3}{2} + \frac{3 3}{2} i

z = - 3, z = \frac{3}{2} - \frac{3 3}{2} i, z = \frac{3}{2} + \frac{3 3}{2} i

- x^{3} + 8 x^{2} + 3 x - 86 = 0

- 7 = t^{7}

x^{3} - 14 x^{2} + 45 x = 0

4 x^{3} - 9 x^{2} = 0

x^{3} + x^{2} - 2 x - 2 = 0

What are the solutions to the equation z^3+27=0 ?
The solutions to the equation z^3+27=0 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i
Find the zeros of z^3+27=0
The zeros of z^3+27=0 are z=-3,z= 3/2-(3sqrt(3))/2 i,z= 3/2+(3sqrt(3))/2 i