What are the solutions to the equation 3(x^2-49)(36x^2-49)=0 ?

The solutions to the equation 3(x^2-49)(36x^2-49)=0 are x=-7,x=7,x=-7/6 ,x= 7/6

Find the zeros of 3(x^2-49)(36x^2-49)=0

The zeros of 3(x^2-49)(36x^2-49)=0 are x=-7,x=7,x=-7/6 ,x= 7/6

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3 (x^{2} - 49) (36 x^{2} - 49) = 0

x = - 7, x = 7, x = - \frac{7}{6}, x = \frac{7}{6}

Decimal Notation

x = - 7, x = 7, x = - 1.16666 \dots, x = 1.16666 \dots

Solution steps

3 (x^{2} - 49) (36 x^{2} - 49) = 0

Factor

3 (x^{2} - 49) (36 x^{2} - 49) : 3 (x + 7) (x - 7) (6 x + 7) (6 x - 7)

3 (x + 7) (x - 7) (6 x + 7) (6 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x - 7 = 0 or 6 x + 7 = 0 or 6 x - 7 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

Solve

6 x + 7 = 0 : x = - \frac{7}{6}

Solve

6 x - 7 = 0 : x = \frac{7}{6}

The solutions are

x = - 7, x = 7, x = - \frac{7}{6}, x = \frac{7}{6}

2 x^{4} - 9 x^{3} + 14 x^{2} - 9 x + 2 = 0

9 x^{4} - 40 x^{2} + 16 = 0

x^{4} - 2 x^{3} + 6 x - 1 = 0

125 x^{3} - 27 = 0

2 x^{3} - x^{2} - 7 x + 6 = 0

What are the solutions to the equation 3(x^2-49)(36x^2-49)=0 ?
The solutions to the equation 3(x^2-49)(36x^2-49)=0 are x=-7,x=7,x=-7/6 ,x= 7/6
Find the zeros of 3(x^2-49)(36x^2-49)=0
The zeros of 3(x^2-49)(36x^2-49)=0 are x=-7,x=7,x=-7/6 ,x= 7/6