What are the solutions to the equation 12x^4=3x^2 ?

The solutions to the equation 12x^4=3x^2 are x=0,x=-1/2 ,x= 1/2

Find the zeros of 12x^4=3x^2

The zeros of 12x^4=3x^2 are x=0,x=-1/2 ,x= 1/2

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12 x^{4} = 3 x^{2}

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5, x = 0.5

Solution steps

12 x^{4} = 3 x^{2}

Move

3 x^{2}

to the left side

12 x^{4} - 3 x^{2} = 0

Factor

12 x^{4} - 3 x^{2} : 3 x^{2} (2 x + 1) (2 x - 1)

3 x^{2} (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

8 x^{3} = 27

x^{3} + 6 x^{2} - 16 x - 96 = 0

s^{3} = - 343

x^{3} + x^{2} = 36 x + 36

x (x^{2} - 3) = 0

What are the solutions to the equation 12x^4=3x^2 ?
The solutions to the equation 12x^4=3x^2 are x=0,x=-1/2 ,x= 1/2
Find the zeros of 12x^4=3x^2
The zeros of 12x^4=3x^2 are x=0,x=-1/2 ,x= 1/2