What are the solutions to the equation 3c^3+9=-72 ?

The solutions to the equation 3c^3+9=-72 are c=-3,c= 3/2-(3sqrt(3))/2 i,c= 3/2+(3sqrt(3))/2 i

Find the zeros of 3c^3+9=-72

The zeros of 3c^3+9=-72 are c=-3,c= 3/2-(3sqrt(3))/2 i,c= 3/2+(3sqrt(3))/2 i

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3 c^{3} + 9 = - 72

c = - 3, c = \frac{3}{2} - \frac{3 3}{2} i, c = \frac{3}{2} + \frac{3 3}{2} i

Solution steps

3 c^{3} + 9 = - 72

Move

9

to the right side

3 c^{3} = - 81

Divide both sides by

3

c^{3} = - 27

For

x^{3} = f (a)

the solutions are

Simplify

c = - 3, c = \frac{3}{2} - \frac{3 3}{2} i, c = \frac{3}{2} + \frac{3 3}{2} i

y^{3} - 5 y^{2} = 0

z^{3} + 2 z^{2} + 21 z - 58 = 0

x^{3} + 4 x^{2} - 36 x - 144 = 0

x^{3} - 9 x^{2} - 4 = 0

2 x^{3} - 5 x^{2} - 3 x = 0

What are the solutions to the equation 3c^3+9=-72 ?
The solutions to the equation 3c^3+9=-72 are c=-3,c= 3/2-(3sqrt(3))/2 i,c= 3/2+(3sqrt(3))/2 i
Find the zeros of 3c^3+9=-72
The zeros of 3c^3+9=-72 are c=-3,c= 3/2-(3sqrt(3))/2 i,c= 3/2+(3sqrt(3))/2 i