What are the solutions to the equation 2x(x+7)(x^2+49)=0 ?

The solutions to the equation 2x(x+7)(x^2+49)=0 are x=0,x=-7,x=7i,x=-7i

Find the zeros of 2x(x+7)(x^2+49)=0

The zeros of 2x(x+7)(x^2+49)=0 are x=0,x=-7,x=7i,x=-7i

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2 x (x + 7) (x^{2} + 49) = 0

x = 0, x = - 7, x = 7 i, x = - 7 i

Solution steps

2 x (x + 7) (x^{2} + 49) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 7 = 0 or x^{2} + 49 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x^{2} + 49 = 0 : x = 7 i, x = - 7 i

The solutions are

x = 0, x = - 7, x = 7 i, x = - 7 i

x^{3} - 12 x = 0

x^{3} - 7 x^{2} - 49 x = - 343

2 x^{4} - 9 x^{2} + 4 = 0

x^{2} - (x - 1)^{3} = 1

- x^{3} + 3 \cdot x + 2 = 0

What are the solutions to the equation 2x(x+7)(x^2+49)=0 ?
The solutions to the equation 2x(x+7)(x^2+49)=0 are x=0,x=-7,x=7i,x=-7i
Find the zeros of 2x(x+7)(x^2+49)=0
The zeros of 2x(x+7)(x^2+49)=0 are x=0,x=-7,x=7i,x=-7i