What are the solutions to the equation (x-3)(x^2+3x+9)=0 ?

The solutions to the equation (x-3)(x^2+3x+9)=0 are x=3,x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2

Find the zeros of (x-3)(x^2+3x+9)=0

The zeros of (x-3)(x^2+3x+9)=0 are x=3,x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2

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(x - 3) (x^{2} + 3 x + 9) = 0

x = 3, x = - \frac{3}{2} + i \frac{3 3}{2}, x = - \frac{3}{2} - i \frac{3 3}{2}

Solution steps

(x - 3) (x^{2} + 3 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} + 3 x + 9 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} + 3 x + 9 = 0 : x = - \frac{3}{2} + i \frac{3 3}{2}, x = - \frac{3}{2} - i \frac{3 3}{2}

The solutions are

x = 3, x = - \frac{3}{2} + i \frac{3 3}{2}, x = - \frac{3}{2} - i \frac{3 3}{2}

6 x^{4} - 24 x^{2} = 0

x^{4} + 2 x^{3} + 2 x^{2} + 2 x + 1 = 0

3 x^{3} - 4 = 0

b^{4} + 7 b^{2} - 18 = 0

(m^{2} + 7 m)^{2} + 5 (m^{2} + 7 m) - 6 = 0

What are the solutions to the equation (x-3)(x^2+3x+9)=0 ?
The solutions to the equation (x-3)(x^2+3x+9)=0 are x=3,x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2
Find the zeros of (x-3)(x^2+3x+9)=0
The zeros of (x-3)(x^2+3x+9)=0 are x=3,x=-3/2+i(3sqrt(3))/2 ,x=-3/2-i(3sqrt(3))/2