What are the solutions to the equation x(2x-1)(x+4)=0 ?

The solutions to the equation x(2x-1)(x+4)=0 are x=0,x= 1/2 ,x=-4

Find the zeros of x(2x-1)(x+4)=0

The zeros of x(2x-1)(x+4)=0 are x=0,x= 1/2 ,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (2 x - 1) (x + 4) = 0

x = 0, x = \frac{1}{2}, x = - 4

Decimal Notation

x = 0, x = 0.5, x = - 4

Solution steps

x (2 x - 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 1 = 0 or x + 4 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 0, x = \frac{1}{2}, x = - 4

x^{4} - 15 x^{2} + 56 = 0

(3 m^{4})^{2} = 3 m^{8}

x^{3} = \frac{1}{125}

x^{3} + 9 x^{2} = 0

x^{2} + 2 = x^{3} - x

What are the solutions to the equation x(2x-1)(x+4)=0 ?
The solutions to the equation x(2x-1)(x+4)=0 are x=0,x= 1/2 ,x=-4
Find the zeros of x(2x-1)(x+4)=0
The zeros of x(2x-1)(x+4)=0 are x=0,x= 1/2 ,x=-4