What are the solutions to the equation 2x(x-5)(x+8)=0 ?

The solutions to the equation 2x(x-5)(x+8)=0 are x=0,x=5,x=-8

Find the zeros of 2x(x-5)(x+8)=0

The zeros of 2x(x-5)(x+8)=0 are x=0,x=5,x=-8

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2 x (x - 5) (x + 8) = 0

x = 0, x = 5, x = - 8

Solution steps

2 x (x - 5) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 5 = 0 or x + 8 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 8 = 0 : x = - 8

The solutions are

x = 0, x = 5, x = - 8

x^{5} + 4 x^{3} = 0

2 x^{3} + 18 x^{2} - 20 x = 0

x^{3} + x - 3 = 0

(a^{3})^{3} = a^{6}

x^{3} + x - 4 = 0

What are the solutions to the equation 2x(x-5)(x+8)=0 ?
The solutions to the equation 2x(x-5)(x+8)=0 are x=0,x=5,x=-8
Find the zeros of 2x(x-5)(x+8)=0
The zeros of 2x(x-5)(x+8)=0 are x=0,x=5,x=-8