What are the solutions to the equation (3x+4)^3=2197 ?

The solutions to the equation (3x+4)^3=2197 are x=3,x=-7/2+i(13sqrt(3))/6 ,x=-7/2-i(13sqrt(3))/6

Find the zeros of (3x+4)^3=2197

The zeros of (3x+4)^3=2197 are x=3,x=-7/2+i(13sqrt(3))/6 ,x=-7/2-i(13sqrt(3))/6

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(3 x + 4)^{3} = 2197

x = 3, x = - \frac{7}{2} + i \frac{13 3}{6}, x = - \frac{7}{2} - i \frac{13 3}{6}

Solution steps

(3 x + 4)^{3} = 2197

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = 3, x = - \frac{7}{2} + i \frac{13 3}{6}, x = - \frac{7}{2} - i \frac{13 3}{6}

x^{3} + 12 x + 2 = 0

- 4 y + 4 y^{3} = 0

x^{3} - 3 = x^{9} + 3

z^{3} = - 2 + 23 i

x^{4} - 3 x^{3} + x - 3 = 0

What are the solutions to the equation (3x+4)^3=2197 ?
The solutions to the equation (3x+4)^3=2197 are x=3,x=-7/2+i(13sqrt(3))/6 ,x=-7/2-i(13sqrt(3))/6
Find the zeros of (3x+4)^3=2197
The zeros of (3x+4)^3=2197 are x=3,x=-7/2+i(13sqrt(3))/6 ,x=-7/2-i(13sqrt(3))/6