What are the solutions to the equation (x^2+16x)^2=17^2 ?

The solutions to the equation (x^2+16x)^2=17^2 are x=1,x=-17,x=-8+sqrt(47),x=-8-sqrt(47)

Find the zeros of (x^2+16x)^2=17^2

The zeros of (x^2+16x)^2=17^2 are x=1,x=-17,x=-8+sqrt(47),x=-8-sqrt(47)

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(x^{2} + 16 x)^{2} = 1 7^{2}

x = 1, x = - 17, x = - 8 + 47, x = - 8 - 47

Decimal Notation

x = 1, x = - 17, x = - 1.14434 \dots, x = - 14.85565 \dots

Solution steps

(x^{2} + 16 x)^{2} = 1 7^{2}

1 7^{2} = 289

(x^{2} + 16 x)^{2} = 289

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x^{2} + 16 x = 289 : x = 1, x = - 17

Solve

x^{2} + 16 x = - 289 : x = - 8 + 47, x = - 8 - 47

The solutions are

x = 1, x = - 17, x = - 8 + 47, x = - 8 - 47

x^{3} - 3 x + 6 = 0

z^{4} - 13 z^{2} + 36 = 0

3 x^{3} + 7 x^{2} - 3 x - 7 = 0

5 x^{4} = 320 x

k^{3} - 9 = 12

What are the solutions to the equation (x^2+16x)^2=17^2 ?
The solutions to the equation (x^2+16x)^2=17^2 are x=1,x=-17,x=-8+sqrt(47),x=-8-sqrt(47)
Find the zeros of (x^2+16x)^2=17^2
The zeros of (x^2+16x)^2=17^2 are x=1,x=-17,x=-8+sqrt(47),x=-8-sqrt(47)