What are the solutions to the equation 3(x^2+3x-10)(x-8)=0 ?

The solutions to the equation 3(x^2+3x-10)(x-8)=0 are x=2,x=-5,x=8

Find the zeros of 3(x^2+3x-10)(x-8)=0

The zeros of 3(x^2+3x-10)(x-8)=0 are x=2,x=-5,x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (x^{2} + 3 x - 10) (x - 8) = 0

x = 2, x = - 5, x = 8

Solution steps

3 (x^{2} + 3 x - 10) (x - 8) = 0

Factor

3 (x^{2} + 3 x - 10) (x - 8) : 3 (x - 2) (x + 5) (x - 8)

3 (x - 2) (x + 5) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 5 = 0 or x - 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 5 = 0 : x = - 5

Solve

x - 8 = 0 : x = 8

The solutions are

x = 2, x = - 5, x = 8

x^{4} - 28 x^{2} + 75 = 0

x^{4} - 7 x^{3} + 12 x^{2} = 0

(x^{2} - x)^{2} - 3 (x^{2} - x) + 2 = 0

2 x^{3} - 12 x^{2} + 18 x = 0

x^{4} - 2 x^{3} + 4 x - 2 = 0

What are the solutions to the equation 3(x^2+3x-10)(x-8)=0 ?
The solutions to the equation 3(x^2+3x-10)(x-8)=0 are x=2,x=-5,x=8
Find the zeros of 3(x^2+3x-10)(x-8)=0
The zeros of 3(x^2+3x-10)(x-8)=0 are x=2,x=-5,x=8