What are the solutions to the equation 0.126825=(1+x)^4-1 ?

The solutions to the equation 0.126825=(1+x)^4-1 are x=\sqrt[4]{1.126825}-1,x=-\sqrt[4]{1.126825}-1

Find the zeros of 0.126825=(1+x)^4-1

The zeros of 0.126825=(1+x)^4-1 are x=\sqrt[4]{1.126825}-1,x=-\sqrt[4]{1.126825}-1

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0.126825 = (1 + x)^{4} - 1

Decimal Notation

x = 0.03030 \dots, x = - 2.03030 \dots

Solution steps

0.126825 = (1 + x)^{4} - 1

Switch sides

(1 + x)^{4} - 1 = 0.126825

Move

1

to the right side

(1 + x)^{4} = 1.126825

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x, - 5 x^{3} - 3 y^{2} = 17

y^{4} - 36 y^{2} = - 35

- 6 + x^{4} = - 5

y - y^{3} = 0

4 x^{3} - 12 x^{2} + 2 x + 6 = 0

What are the solutions to the equation 0.126825=(1+x)^4-1 ?
The solutions to the equation 0.126825=(1+x)^4-1 are x=\sqrt[4]{1.126825}-1,x=-\sqrt[4]{1.126825}-1
Find the zeros of 0.126825=(1+x)^4-1
The zeros of 0.126825=(1+x)^4-1 are x=\sqrt[4]{1.126825}-1,x=-\sqrt[4]{1.126825}-1