What are the solutions to the equation (x+7)(x^2-49)=0 ?

The solutions to the equation (x+7)(x^2-49)=0 are x=-7,x=7

Find the zeros of (x+7)(x^2-49)=0

The zeros of (x+7)(x^2-49)=0 are x=-7,x=7

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(x + 7) (x^{2} - 49) = 0

x = - 7, x = 7

Solution steps

(x + 7) (x^{2} - 49) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x^{2} - 49 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x^{2} - 49 = 0 : x = 7, x = - 7

The solutions are

x = - 7, x = 7

16 x^{4} + 9 = 25 x^{2}

x^{3} - 3 x - 7 = 0

4 x^{4} - 5 x^{2} + 4 = 0

r^{3} - 3 r^{2} + 3 r - 1 = 0

x^{4} - 3 x^{2} - 28 = 0

What are the solutions to the equation (x+7)(x^2-49)=0 ?
The solutions to the equation (x+7)(x^2-49)=0 are x=-7,x=7
Find the zeros of (x+7)(x^2-49)=0
The zeros of (x+7)(x^2-49)=0 are x=-7,x=7