What are the solutions to the equation 1=3(2+x/3)^9 ?

The solutions to the equation 1=3(2+x/3)^9 are x=\sqrt[9]{6561}-6

Find the zeros of 1=3(2+x/3)^9

The zeros of 1=3(2+x/3)^9 are x=\sqrt[9]{6561}-6

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1 = 3 (2 + \frac{x}{3})^{9}

Decimal Notation

x = - 3.34473 \dots

Solution steps

1 = 3 (2 + \frac{x}{3})^{9}

Switch sides

3 (2 + \frac{x}{3})^{9} = 1

Divide both sides by

3

(2 + \frac{x}{3})^{9} = \frac{1}{3}

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

(z - 1)^{4} = 1

x^{3} + 7 x^{2} + 10 x = 0

x, x^{3} + y = 0

15 x^{4} - 13 x^{2} + 2 = 0

x, 905 = 5 x^{3}

What are the solutions to the equation 1=3(2+x/3)^9 ?
The solutions to the equation 1=3(2+x/3)^9 are x=\sqrt[9]{6561}-6
Find the zeros of 1=3(2+x/3)^9
The zeros of 1=3(2+x/3)^9 are x=\sqrt[9]{6561}-6