What are the solutions to the equation a=(x-3)^{10}+1 ?

The solutions to the equation a=(x-3)^{10}+1 are x=\sqrt[10]{a-1}+3,x=-\sqrt[10]{a-1}+3

Find the zeros of a=(x-3)^{10}+1

The zeros of a=(x-3)^{10}+1 are x=\sqrt[10]{a-1}+3,x=-\sqrt[10]{a-1}+3

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a = (x - 3)^{10} + 1

Solution steps

a = (x - 3)^{10} + 1

Switch sides

(x - 3)^{10} + 1 = a

Move

1

to the right side

(x - 3)^{10} = a - 1

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x^{3} - 3 x^{2} - 18 x = 0

x, x^{4} + 2 x^{2} y^{2} = 0

x (x + 1) (x + 2) = 63 (x + 1)

2 x^{3} + 9 = x^{2} + 18 x

36 x^{3} = 144 x

What are the solutions to the equation a=(x-3)^{10}+1 ?
The solutions to the equation a=(x-3)^{10}+1 are x=\sqrt[10]{a-1}+3,x=-\sqrt[10]{a-1}+3
Find the zeros of a=(x-3)^{10}+1
The zeros of a=(x-3)^{10}+1 are x=\sqrt[10]{a-1}+3,x=-\sqrt[10]{a-1}+3