What are the solutions to the equation x^3-4x^2+9x-36=0 ?

The solutions to the equation x^3-4x^2+9x-36=0 are x=4,x=3i,x=-3i

Find the zeros of x^3-4x^2+9x-36=0

The zeros of x^3-4x^2+9x-36=0 are x=4,x=3i,x=-3i

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x^{3} - 4 x^{2} + 9 x - 36 = 0

x = 4, x = 3 i, x = - 3 i

Solution steps

x^{3} - 4 x^{2} + 9 x - 36 = 0

Factor

x^{3} - 4 x^{2} + 9 x - 36 : (x - 4) (x^{2} + 9)

(x - 4) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x^{2} + 9 = 0

Solve

x - 4 = 0 : x = 4

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = 4, x = 3 i, x = - 3 i

x^{4} - 8 x^{3} + 24 x^{2} - 32 x + 16 = 0

x^{4} - 4 x^{3} + x^{2} - 5 x = 3

x^{7} - 6 x^{5} - x^{2} + x - 7 = 0

2 (x^{2} - 100) (36 x^{2} - 49) = 0

6 x^{4} - 9 x^{3} = 0

What are the solutions to the equation x^3-4x^2+9x-36=0 ?
The solutions to the equation x^3-4x^2+9x-36=0 are x=4,x=3i,x=-3i
Find the zeros of x^3-4x^2+9x-36=0
The zeros of x^3-4x^2+9x-36=0 are x=4,x=3i,x=-3i