What are the solutions to the equation (9k-1)^2=-8 ?

The solutions to the equation (9k-1)^2=-8 are k= 1/9+i(2sqrt(2))/9 ,k= 1/9-i(2sqrt(2))/9

Find the zeros of (9k-1)^2=-8

The zeros of (9k-1)^2=-8 are k= 1/9+i(2sqrt(2))/9 ,k= 1/9-i(2sqrt(2))/9

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(9 k - 1)^{2} = - 8

k = \frac{1}{9} + i \frac{2 2}{9}, k = \frac{1}{9} - i \frac{2 2}{9}

Solution steps

(9 k - 1)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

9 k - 1 = - 8 : k = \frac{1}{9} + i \frac{2 2}{9}

Solve

9 k - 1 = - - 8 : k = \frac{1}{9} - i \frac{2 2}{9}

The solutions to the quadratic equation are:

k = \frac{1}{9} + i \frac{2 2}{9}, k = \frac{1}{9} - i \frac{2 2}{9}

y^{2} + 6 y - 27

81 x^{2} - 9

- 2 \leq x - 11 \leq 6

(1 + i) (9 - 8 i)

x^{2} - 3 x^{2} - 10

What are the solutions to the equation (9k-1)^2=-8 ?
The solutions to the equation (9k-1)^2=-8 are k= 1/9+i(2sqrt(2))/9 ,k= 1/9-i(2sqrt(2))/9
Find the zeros of (9k-1)^2=-8
The zeros of (9k-1)^2=-8 are k= 1/9+i(2sqrt(2))/9 ,k= 1/9-i(2sqrt(2))/9