What are the solutions to the equation (12x^2+1)^2=0 ?

The solutions to the equation (12x^2+1)^2=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i

Find the zeros of (12x^2+1)^2=0

The zeros of (12x^2+1)^2=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i

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(12 x^{2} + 1)^{2} = 0

x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

Solution steps

(12 x^{2} + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

12 x^{2} + 1 = 0 : x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

The solutions are

x = \frac{1}{2 3} i, x = - \frac{1}{2 3} i

x, y - x^{3} = 0

2 x^{3} - 3 x^{2} - 17 x + 30 = 0

2 x^{5} - 14 x^{3} = 0

x^{3} - 2 x^{2} + x = 2

(2 x + 3) (1 - x) (x - 6) = 0

What are the solutions to the equation (12x^2+1)^2=0 ?
The solutions to the equation (12x^2+1)^2=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i
Find the zeros of (12x^2+1)^2=0
The zeros of (12x^2+1)^2=0 are x= 1/(2sqrt(3))i,x=-1/(2sqrt(3))i