What are the solutions to the equation 3(x^2-64)(x^2+64)=0 ?

The solutions to the equation 3(x^2-64)(x^2+64)=0 are x=-8,x=8,x=8i,x=-8i

Find the zeros of 3(x^2-64)(x^2+64)=0

The zeros of 3(x^2-64)(x^2+64)=0 are x=-8,x=8,x=8i,x=-8i

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3 (x^{2} - 64) (x^{2} + 64) = 0

x = - 8, x = 8, x = 8 i, x = - 8 i

Solution steps

3 (x^{2} - 64) (x^{2} + 64) = 0

Factor

3 (x^{2} - 64) (x^{2} + 64) : 3 (x + 8) (x - 8) (x^{2} + 64)

3 (x + 8) (x - 8) (x^{2} + 64) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or x - 8 = 0 or x^{2} + 64 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x - 8 = 0 : x = 8

Solve

x^{2} + 64 = 0 : x = 8 i, x = - 8 i

The solutions are

x = - 8, x = 8, x = 8 i, x = - 8 i

27 x - 9 = 3 x^{3} - x^{2}

- x^{3} - x^{2} + 2 x = 0

x, y^{2} - x^{3} + 8 = 0

- 2 x^{4} + 9 = 3 x + 2

2 x^{3} + x - 1 = 0

What are the solutions to the equation 3(x^2-64)(x^2+64)=0 ?
The solutions to the equation 3(x^2-64)(x^2+64)=0 are x=-8,x=8,x=8i,x=-8i
Find the zeros of 3(x^2-64)(x^2+64)=0
The zeros of 3(x^2-64)(x^2+64)=0 are x=-8,x=8,x=8i,x=-8i